Optimal. Leaf size=238 \[ \frac{139 a^2}{224 d (a \sec (c+d x)+a)^{7/2}}-\frac{19 a^2}{16 d (1-\sec (c+d x)) (a \sec (c+d x)+a)^{7/2}}-\frac{a^2}{4 d (1-\sec (c+d x))^2 (a \sec (c+d x)+a)^{7/2}}+\frac{2 \tanh ^{-1}\left (\frac{\sqrt{a \sec (c+d x)+a}}{\sqrt{a}}\right )}{a^{3/2} d}-\frac{203 \tanh ^{-1}\left (\frac{\sqrt{a \sec (c+d x)+a}}{\sqrt{2} \sqrt{a}}\right )}{256 \sqrt{2} a^{3/2} d}+\frac{15 a}{64 d (a \sec (c+d x)+a)^{5/2}}-\frac{53}{384 d (a \sec (c+d x)+a)^{3/2}}-\frac{309}{256 a d \sqrt{a \sec (c+d x)+a}} \]
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Rubi [A] time = 0.204777, antiderivative size = 238, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 7, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.304, Rules used = {3880, 103, 151, 152, 156, 63, 207} \[ \frac{139 a^2}{224 d (a \sec (c+d x)+a)^{7/2}}-\frac{19 a^2}{16 d (1-\sec (c+d x)) (a \sec (c+d x)+a)^{7/2}}-\frac{a^2}{4 d (1-\sec (c+d x))^2 (a \sec (c+d x)+a)^{7/2}}+\frac{2 \tanh ^{-1}\left (\frac{\sqrt{a \sec (c+d x)+a}}{\sqrt{a}}\right )}{a^{3/2} d}-\frac{203 \tanh ^{-1}\left (\frac{\sqrt{a \sec (c+d x)+a}}{\sqrt{2} \sqrt{a}}\right )}{256 \sqrt{2} a^{3/2} d}+\frac{15 a}{64 d (a \sec (c+d x)+a)^{5/2}}-\frac{53}{384 d (a \sec (c+d x)+a)^{3/2}}-\frac{309}{256 a d \sqrt{a \sec (c+d x)+a}} \]
Antiderivative was successfully verified.
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Rule 3880
Rule 103
Rule 151
Rule 152
Rule 156
Rule 63
Rule 207
Rubi steps
\begin{align*} \int \frac{\cot ^5(c+d x)}{(a+a \sec (c+d x))^{3/2}} \, dx &=\frac{a^6 \operatorname{Subst}\left (\int \frac{1}{x (-a+a x)^3 (a+a x)^{9/2}} \, dx,x,\sec (c+d x)\right )}{d}\\ &=-\frac{a^2}{4 d (1-\sec (c+d x))^2 (a+a \sec (c+d x))^{7/2}}-\frac{a^3 \operatorname{Subst}\left (\int \frac{4 a^2+\frac{11 a^2 x}{2}}{x (-a+a x)^2 (a+a x)^{9/2}} \, dx,x,\sec (c+d x)\right )}{4 d}\\ &=-\frac{a^2}{4 d (1-\sec (c+d x))^2 (a+a \sec (c+d x))^{7/2}}-\frac{19 a^2}{16 d (1-\sec (c+d x)) (a+a \sec (c+d x))^{7/2}}+\frac{\operatorname{Subst}\left (\int \frac{8 a^4+\frac{171 a^4 x}{4}}{x (-a+a x) (a+a x)^{9/2}} \, dx,x,\sec (c+d x)\right )}{8 d}\\ &=\frac{139 a^2}{224 d (a+a \sec (c+d x))^{7/2}}-\frac{a^2}{4 d (1-\sec (c+d x))^2 (a+a \sec (c+d x))^{7/2}}-\frac{19 a^2}{16 d (1-\sec (c+d x)) (a+a \sec (c+d x))^{7/2}}-\frac{\operatorname{Subst}\left (\int \frac{-56 a^6-\frac{973 a^6 x}{8}}{x (-a+a x) (a+a x)^{7/2}} \, dx,x,\sec (c+d x)\right )}{56 a^3 d}\\ &=\frac{139 a^2}{224 d (a+a \sec (c+d x))^{7/2}}-\frac{a^2}{4 d (1-\sec (c+d x))^2 (a+a \sec (c+d x))^{7/2}}-\frac{19 a^2}{16 d (1-\sec (c+d x)) (a+a \sec (c+d x))^{7/2}}+\frac{15 a}{64 d (a+a \sec (c+d x))^{5/2}}+\frac{\operatorname{Subst}\left (\int \frac{280 a^8+\frac{2625 a^8 x}{16}}{x (-a+a x) (a+a x)^{5/2}} \, dx,x,\sec (c+d x)\right )}{280 a^6 d}\\ &=\frac{139 a^2}{224 d (a+a \sec (c+d x))^{7/2}}-\frac{a^2}{4 d (1-\sec (c+d x))^2 (a+a \sec (c+d x))^{7/2}}-\frac{19 a^2}{16 d (1-\sec (c+d x)) (a+a \sec (c+d x))^{7/2}}+\frac{15 a}{64 d (a+a \sec (c+d x))^{5/2}}-\frac{53}{384 d (a+a \sec (c+d x))^{3/2}}-\frac{\operatorname{Subst}\left (\int \frac{-840 a^{10}+\frac{5565 a^{10} x}{32}}{x (-a+a x) (a+a x)^{3/2}} \, dx,x,\sec (c+d x)\right )}{840 a^9 d}\\ &=\frac{139 a^2}{224 d (a+a \sec (c+d x))^{7/2}}-\frac{a^2}{4 d (1-\sec (c+d x))^2 (a+a \sec (c+d x))^{7/2}}-\frac{19 a^2}{16 d (1-\sec (c+d x)) (a+a \sec (c+d x))^{7/2}}+\frac{15 a}{64 d (a+a \sec (c+d x))^{5/2}}-\frac{53}{384 d (a+a \sec (c+d x))^{3/2}}-\frac{309}{256 a d \sqrt{a+a \sec (c+d x)}}+\frac{\operatorname{Subst}\left (\int \frac{840 a^{12}-\frac{32445 a^{12} x}{64}}{x (-a+a x) \sqrt{a+a x}} \, dx,x,\sec (c+d x)\right )}{840 a^{12} d}\\ &=\frac{139 a^2}{224 d (a+a \sec (c+d x))^{7/2}}-\frac{a^2}{4 d (1-\sec (c+d x))^2 (a+a \sec (c+d x))^{7/2}}-\frac{19 a^2}{16 d (1-\sec (c+d x)) (a+a \sec (c+d x))^{7/2}}+\frac{15 a}{64 d (a+a \sec (c+d x))^{5/2}}-\frac{53}{384 d (a+a \sec (c+d x))^{3/2}}-\frac{309}{256 a d \sqrt{a+a \sec (c+d x)}}+\frac{203 \operatorname{Subst}\left (\int \frac{1}{(-a+a x) \sqrt{a+a x}} \, dx,x,\sec (c+d x)\right )}{512 d}-\frac{\operatorname{Subst}\left (\int \frac{1}{x \sqrt{a+a x}} \, dx,x,\sec (c+d x)\right )}{a d}\\ &=\frac{139 a^2}{224 d (a+a \sec (c+d x))^{7/2}}-\frac{a^2}{4 d (1-\sec (c+d x))^2 (a+a \sec (c+d x))^{7/2}}-\frac{19 a^2}{16 d (1-\sec (c+d x)) (a+a \sec (c+d x))^{7/2}}+\frac{15 a}{64 d (a+a \sec (c+d x))^{5/2}}-\frac{53}{384 d (a+a \sec (c+d x))^{3/2}}-\frac{309}{256 a d \sqrt{a+a \sec (c+d x)}}-\frac{2 \operatorname{Subst}\left (\int \frac{1}{-1+\frac{x^2}{a}} \, dx,x,\sqrt{a+a \sec (c+d x)}\right )}{a^2 d}+\frac{203 \operatorname{Subst}\left (\int \frac{1}{-2 a+x^2} \, dx,x,\sqrt{a+a \sec (c+d x)}\right )}{256 a d}\\ &=\frac{2 \tanh ^{-1}\left (\frac{\sqrt{a+a \sec (c+d x)}}{\sqrt{a}}\right )}{a^{3/2} d}-\frac{203 \tanh ^{-1}\left (\frac{\sqrt{a+a \sec (c+d x)}}{\sqrt{2} \sqrt{a}}\right )}{256 \sqrt{2} a^{3/2} d}+\frac{139 a^2}{224 d (a+a \sec (c+d x))^{7/2}}-\frac{a^2}{4 d (1-\sec (c+d x))^2 (a+a \sec (c+d x))^{7/2}}-\frac{19 a^2}{16 d (1-\sec (c+d x)) (a+a \sec (c+d x))^{7/2}}+\frac{15 a}{64 d (a+a \sec (c+d x))^{5/2}}-\frac{53}{384 d (a+a \sec (c+d x))^{3/2}}-\frac{309}{256 a d \sqrt{a+a \sec (c+d x)}}\\ \end{align*}
Mathematica [C] time = 0.265213, size = 99, normalized size = 0.42 \[ \frac{\cot ^4(c+d x) \left (203 (\sec (c+d x)-1)^2 \text{Hypergeometric2F1}\left (-\frac{7}{2},1,-\frac{5}{2},\frac{1}{2} (\sec (c+d x)+1)\right )-64 (\sec (c+d x)-1)^2 \text{Hypergeometric2F1}\left (-\frac{7}{2},1,-\frac{5}{2},\sec (c+d x)+1\right )+266 \sec (c+d x)-322\right )}{224 d (a (\sec (c+d x)+1))^{3/2}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.276, size = 866, normalized size = 3.6 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: UnboundLocalError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 10.0635, size = 481, normalized size = 2.02 \begin{align*} -\frac{\frac{4263 \, \sqrt{2} \arctan \left (\frac{\sqrt{-a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a}}{\sqrt{-a}}\right )}{\sqrt{-a} a \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )} - \frac{21504 \, \arctan \left (\frac{\sqrt{2} \sqrt{-a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a}}{2 \, \sqrt{-a}}\right )}{\sqrt{-a} a \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )} - \frac{21 \, \sqrt{2}{\left (29 \,{\left (-a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a\right )}^{\frac{3}{2}} - 27 \, \sqrt{-a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a} a\right )}}{a^{3} \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right ) \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4}} + \frac{8 \,{\left (3 \, \sqrt{2}{\left (a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - a\right )}^{3} \sqrt{-a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a} a^{30} - 21 \, \sqrt{2}{\left (a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - a\right )}^{2} \sqrt{-a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a} a^{31} - 112 \, \sqrt{2}{\left (-a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a\right )}^{\frac{3}{2}} a^{32} - 882 \, \sqrt{2} \sqrt{-a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a} a^{33}\right )}}{a^{35} \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )}}{10752 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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